Killtest Practice Exams for 1z1-238 are written to the highest standards of technical accuracy, using only certified subject matter experts and published authors for development.100% Guarantee to Pass Your Other Oracle Certification exam and get your Other Oracle Certification Certification.
We guarantee your success in the first attempt. If you do not pass the Other Oracle Certification 1z1-238 (R12 Oracle: install,Patch and Maintain Oracle Applications) on your first attempt we will give you a FULL REFUND of your purchasing fee AND send you another same value product for free.
killtest 1z1-238 Downloadable.
Printable Exams (in PDF format) Our Exam 1z1-238 Preparation Material provides you everything you will need to take your Other Oracle Certification exam. The Other Oracle Certification Certification details are researched and produced by Professional Certification Experts who are constantly using industry experience to produce precise, and logical. You may get Other Oracle Certification exam questions from different web sites or books, but logic is the key. Our Product will help you not only pass in the first Other Oracle Certification exam try, but also save your valuable time
3. Which statement is true regarding the default behavior of the ORDER BY clause?
A.In a character sort, the values are case-sensitive.
B.NULL values are not considered at all by the sort operation.
C.Only those columns that are specified in the SELECT list can be used in the ORDER BY clause.
D.Numeric values are displayed from the maximum to the minimum value if they have decimal positions.
Answer: A
4. Examine the structure and data in the PRICE_LIST table:
Name Null? Type
————– ——– —————-
PROD_ID NOT NULL NUMBER(3)
PROD_PRICE VARCHAR2(10)
PROD_ID PROD_PRICE
——- ———-
100 $234.55
101 $6,509.75
102 $1,234
You plan to give a discount of 25% on the product price and need to display the discount amount in the same format as the PROD_PRICE.
Which SQL statement would give the required result?
A.SELECT TO_CHAR(prod_price* .25,’$99,999.99′) FROM PRICE_LIST;
B.SELECT TO_CHAR(TO_NUMBER(prod_price)* .25,’$99,999.00′) FROM PRICE_LIST;
C.SELECT TO_CHAR(TO_NUMBER(prod_price,’$99,999.99′)* .25,’$99,999.00′) FROM PRICE_LIST;
D.SELECT TO_NUMBER(TO_NUMBER(prod_price,’$99,999.99′)* .25,’$99,999.00′) FROM PRICE_LIST;
Answer: C